12x^2+1x=35

Solution for 12x^2+1x=35 equation:

12x^2+1x=35

We move all terms to the left:

12x^2+1x-(35)=0

We add all the numbers together, and all the variables

12x^2+x-35=0

a = 12; b = 1; c = -35;
Δ = b2-4ac
Δ = 12-4·12·(-35)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1681}=41$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-41}{2*12}=\frac{-42}{24}
=-1+3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+41}{2*12}=\frac{40}{24}
=1+2/3
$